2x^2+18x+28=14

Solution for 2x^2+18x+28=14 equation:

2x^2+18x+28=14

We move all terms to the left:

2x^2+18x+28-(14)=0

We add all the numbers together, and all the variables

2x^2+18x+14=0

a = 2; b = 18; c = +14;
Δ = b2-4ac
Δ = 182-4·2·14
Δ = 212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{212}=\sqrt{4*53}=\sqrt{4}*\sqrt{53}=2\sqrt{53}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{53}}{2*2}=\frac{-18-2\sqrt{53}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{53}}{2*2}=\frac{-18+2\sqrt{53}}{4}
$